This page covers the following topics:
In Java SE 7 and later, a single catch
block can
handle more than one type of exception. This feature can reduce
code duplication and lessen the temptation to catch an overly broad
exception.
Consider the following example, which contains duplicate code in
each of the catch
blocks:
catch (IOException ex) { logger.log(ex); throw ex; } catch (SQLException ex) { logger.log(ex); throw ex; }
In releases prior to Java SE 7, it is difficult to create a
common method to eliminate the duplicated code because the variable
ex
has different types.
The following example, which is valid in Java SE 7 and later, eliminates the duplicated code:
catch (IOException|SQLException ex) { logger.log(ex); throw ex; }
The catch
clause specifies the types of exceptions
that the block can handle, and each exception type is separated
with a vertical bar (|
).
Note: If a catch
block handles
more than one exception type, then the catch
parameter
is implicitly final
. In this example, the
catch
parameter ex
is final
and therefore you cannot assign any values to it within the
catch
block.
Bytecode generated by compiling a catch
block that
handles multiple exception types will be smaller (and thus
superior) than compiling many catch
blocks that handle
only one exception type each. A catch
block that
handles multiple exception types creates no duplication in the
bytecode generated by the compiler; the bytecode has no replication
of exception handlers.
The Java SE 7 compiler performs more precise analysis of
rethrown exceptions than earlier releases of Java SE. This enables
you to specify more specific exception types in the
throws
clause of a method declaration.
Consider the following example:
static class FirstException extends Exception { } static class SecondException extends Exception { } public void rethrowException(String exceptionName) throws Exception { try { if (exceptionName.equals("First")) { throw new FirstException(); } else { throw new SecondException(); } } catch (Exception e) { throw e; } }
This examples's try
block could throw either
FirstException
or SecondException
.
Suppose you want to specify these exception types in the
throws
clause of the rethrowException
method declaration. In releases prior to Java SE 7, you cannot do
so. Because the exception parameter of the catch
clause, e
, is type Exception
, and the
catch block rethrows the exception parameter e
, you
can only specify the exception type Exception
in the
throws
clause of the rethrowException
method declaration.
However, in Java SE 7, you can specify the exception types
FirstException
and SecondException
in the
throws
clause in the rethrowException
method declaration. The Java SE 7 compiler can determine that the
exception thrown by the statement throw e
must have
come from the try
block, and the only exceptions
thrown by the try
block can be
FirstException
and SecondException
. Even
though the exception parameter of the catch
clause,
e
, is type Exception
, the compiler can
determine that it is an instance of either
FirstException
or SecondException
:
public void rethrowException(String exceptionName) throws FirstException, SecondException { try { // ... } catch (Exception e) { throw e; } }
This analysis is disabled if the catch
parameter is
assigned to another value in the catch
block. However,
if the catch parameter is assigned to another value, you must
specify the exception type Exception
in the
throws
clause of the method declaration.
In detail, in Java SE 7 and later, when you declare one or more
exception types in a catch
clause, and rethrow the
exception handled by this catch
block, the compiler
verifies that the type of the rethrown exception meets the
following conditions:
try
block is able to throw it.catch
blocks that can
handle it.catch
clause's exception parameters.The Java SE 7 compiler allows you to specify the exception types
FirstException
and SecondException
in the
throws
clause in the rethrowException
method declaration because you can rethrow an exception that is a
supertype of any of the types declared in the
throws
.
In releases prior to Java SE 7, you cannot throw an exception
that is a supertype of one of the catch
clause's
exception parameters. A compiler from a release prior to Java SE 7
generates the error, "unreported exception Exception
;
must be caught or declared to be thrown" at the statement
throw e
. The compiler checks if the type of the
exception thrown is assignable to any of the types declared in the
throws
clause of the rethrowException
method declaration. However, the type of the catch parameter
e
is Exception
, which is a supertype, not
a subtype, of FirstException
andSecondException
.